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Which equation has an a-value of 1, a b-value of –3, and a c-value of –5?

0 = –3x – 5 + x2
0 = x – 3 – 5x2
0 = 3x – 5 – x2
0 = –3x + 5 – x2

Respuesta :

Answer:

Option (a) is correct.

For given values a = 1 , b = -3 , c = -5 the quadratic equation is  

Step-by-step explanation:

Given : a = 1 , b = -3 , c = -5

We have to write the quadratic equation having a = 1 , b = -3 , c = -5 and choose the correct option.

The standard form of quadratic equation is  , where a, b, c are constant integers.

Given : a = 1 , b = -3 , c = -5

Then Substitute, we get,

 

Thus, the obtained quadratic equation is same as option (a)

Thus, For given values a = 1 , b = -3 , c = -5 the quadratic equation is

The equation for which a-value 1, ab-value -3 and ac-value -5 is 0=-3x-5+x².

What is quadratic equation?

Quadratics can be defined as a polynomial equation of a second degree, which implies that it comprises a minimum of one term that is squared. It is also called quadratic equations.

Here, a-value = 1,

        ab-value =  -3

        ac-value = -5

a = 1, b = -3, and c = -5

General Equation,

ax² + bx + c = 0

1x² + (-3)x + (-5) = 0

x² -3x -5 = 0

Thus, the equation for which a-value 1, ab-value -3 and ac-value -5 is 0= -3x -5 + x².

Learn more about Quadratic Equation from:

https://brainly.com/question/1863222

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