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Suppose a basketball player is an excellent free throw shooter and makes 90% of his free throws (i.e., he has a 90% chance of making a single free throw). Assume that free throw shots are independent of one another. Find the probability that the player misses three consecutive free throws. 0.729 0.271 0.001 0.999

Respuesta :

Answer:

The answer is "0.001 ".

Step-by-step explanation:

In this question, the shot value is missing So its solution can be defined a follows:

let

shot value= 3

The chances of missing a free takeoff [tex]= 1- 0.90 = 0.1[/tex]

All three free throws are probably gone[tex]= 0.1^3 = 0.001[/tex]

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