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Line JK passes through points J(–3, 11) and K(1, –3). What is the equation of line JK in standard form?

Respuesta :

Kianagruber
(11 - (-3))/(-3 - 1) = 14/-4 = -7/2

y + 3 = -7/2(x - 1)

2y + 6 = -7x + 7

7x + 2y = 7 - 6

7x + 2y = 1
minarohani7
i thought the correct answer will be k (1, -3)

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