savanamorales savanamorales

30-11-2016
Mathematics

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Evaluate cos((Sin^-1)0)

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wizard123 wizard123

30-11-2016

First evaluate
[tex]sin^{-1} (0)[/tex]
what angles in domain of [-pi/2, pi/2] make sin = 0
[tex]\theta = 0[/tex]
Now we can evaluate the cos function:
[tex]cos (0) = 1[/tex]

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