Name an angle of
B) 50°

Answer:
∠BFC = 50
Step-by-step explanation:
∠AFC = 90
∠AFB + ∠BFC = 90
40 + ∠BFC = 90
∠BFC = 90 - 40
∠BFC = 50
Answer: B-C
Step-by-step explanation:
I believe it is the angle of B-C becuase B-E is a strieght line which equals 180. Also EFD looks the same as AFB so it is 40. And DFC is 90 becuase of the square. So we take 180-40-90=50. And the only one that is not solved is B-C