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what is the approximate percent increase when the population of a town increases from 12089 to 15025? round the amounts to the nearest ten thousand.

Respuesta :

bartdrinksmalk
The rate of increase is
[tex]\frac{15025}{12089}\approx1.242865[/tex]

The percent of increase is then
[tex](1.242865-1)*100\%=0.242865*100\%=24.2865\%[/tex]
bcalle
15025-12089 = 2936 2936/12089 = .2429 .2429 * 100 = 24.29% or Approx 24 %

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