find the measure of the exterior angle

Answer:
[tex] \huge\mathfrak\pink{S} \huge\mathfrak\purple{o} \huge\mathfrak\blue{l} \huge\mathfrak\red{u} \huge\mathfrak\green{t} \huge\mathfrak\pink{i}\huge\mathfrak\purple{o}\huge\mathfrak\red{n}\huge\mathfrak\orange{➔}\ [/tex]
2a=a+10+44°[exterior angle of a triangle is equal to the sum of two opposite interior angle]
2a-a=54°
a=54°
.so
exterior angle=2×54°=108°is your answer