Respuesta :
Answer:
- 6 in and 15 in
Step-by-step explanation:
Given:
- l = 2w + 3
- A = 90 in²
- w = ?
- l = ?
Area formula:
- A = lw
Substitute values and solve for w:
- (2w+3)w = 90
- 2w² + 3w = 90
- 2w² + 3w - 90 = 0
- w = (-3 ± [tex]\sqrt{3^2 - 4*2*(-90)}[/tex])/2*2
- w = (-3 ± √729)/4
- w = (-3 ± 27)/4
- w = 6 (positive root only)
The width is 6 in, find the length:
- l = 2*6 + 3 = 15 in
width be x
- Length be 2x+3
Now
- area=Length×Breadth
- x(2x+3)=90
- 2x²+3x=90
- 2x²+3x-90=0
On solving we will get
- x=6[Take positive]
Now
Length=2(6)=3=15in