Find the value of x in the triangle shown below.
a. x=4
b.x=5
c.x=2
d.x=32

Answer:
Answer:[tex] \huge\mathfrak\pink{S} \huge\mathfrak\purple{o} \huge\mathfrak\blue{l} \huge\mathfrak\red{u} \huge\mathfrak\green{t} \huge\mathfrak\pink{i}\huge\mathfrak\purple{o}\huge\mathfrak\red{n}\huge\mathfrak\orange{➔}\ [/tex]by using Pythagoras law:h²=p²+b²
9²=x²+7²
x²=81-49
x=√32units