Answer:
607 students
Step-by-step explanation:
To solve this question means we have to use Pigenhole principle which states that if y number of items are put into z number of containers, with y > z, then it means that that at least one container must definitely contain more than one item.
Now, let's find the number of boxes and objects:
If possible scores are from 0 to 100 with both inclusive it means number of possible scores = 101.
Now, If there was only one professor grading the students, in order to ensure that that there are two students with the same professor who earned the same final examination score,
The number of students would have to be = 101 + 1 = 102 students
Meanwhile, for each student, since there are 6 professors, the possible combination for a score will be = 6 possible combinations.
Therefore, number of students that will guarantee that there are two students with the same professor who earned the same final examination score must be a minimum of: (6 × 101) + 1 = 607