The radius of the base of a cone is 4 inches. The slant height of the cone is 6 inches. Which is closest to the surface area of the cone ?
[tex] \bullet [/tex] Radius (r) of the base of a cone is 4 inches.
[tex] \bullet [/tex] Slant height (l) of the cone is 6 inches.
Which is closest to the surface area of the cone ?
We know,
Formula of surface area of a cone is πr(r + l) sq. units.
Taking value of π = 3.14
So, Surface area of the cone = 3.14 × 4(4 + 6)
Surface area of the cone = 12.56 × 10
Surface area of the cone = 125.6 sq. inches.
[tex] \because [/tex] 126 sq. inches is closest to 125.6 sq. inches.
So, option (H) 126 sq. in is correct. [Answer]