The radius of the base of a cone is 4 inches. The slant height of the cone is
6 inches. Which is closest to the surface area of the cone?
F 75 sq in.
100 sq in.
H 126 sq in.
J 188 sq in.

Respuesta :

Question:-

The radius of the base of a cone is 4 inches. The slant height of the cone is 6 inches. Which is closest to the surface area of the cone ?

Answer:-

Given:-

[tex] \bullet [/tex] Radius (r) of the base of a cone is 4 inches.

[tex] \bullet [/tex] Slant height (l) of the cone is 6 inches.

To Find:-

Which is closest to the surface area of the cone ?

Solution:-

We know,

Formula of surface area of a cone is πr(r + l) sq. units.

Taking value of π = 3.14

So, Surface area of the cone = 3.14 × 4(4 + 6)

Surface area of the cone = 12.56 × 10

Surface area of the cone = 125.6 sq. inches.

[tex] \because [/tex] 126 sq. inches is closest to 125.6 sq. inches.

So, option (H) 126 sq. in is correct. [Answer]