Respuesta :

mhanifa

Answer:

Given GP:

  • tₙ = (1/3)ⁿ⁻¹

We see that:

  • t₁ = 1, r = 1/3

Sum of  n terms:

  • Sₙ = t₁(1 - rⁿ)/(1 - r)
  • Sₙ = [1 - (1/3)ⁿ] / (1 - 1/3) = [1 - (1/3)ⁿ] / (2/3) = 3/2 [1 - (1/3)ⁿ]
  • Sₙ = 3/2 [1 - (1/3)ⁿ]

Otras preguntas