contestada

The anion sbf4− does not obey the octet rule. draw its lewis structure and state the type of octet-rule exception. indicate the values of nonzero formal charges and include lone pair electrons.

Respuesta :

pstnonsonjoku

Answer:

SEE EXPLANATION

Explanation:

The ion SbF4^- is octahedral in shape. In this compound, Sb which is the central atom in SbF4^- has an expanded octet. This means that it has more than eight electrons in its outermost shell thereby violating the octet rule. Hence the type of violation to the octet rule shown by the compound is expanded octet.

The Sb central atom has a formal charge of -1 as shown in the image attached to this answer.

Ver imagen pstnonsonjoku