Answer:
a-The equation for processor only configuration is [tex]120\times 10^6=\dfrac{I+YF}{W}\\[/tex] while that for processor and co-processor configuration is [tex]80\times10^6=\dfrac{I+F}{B}[/tex].
b-The value of B is 1.1 second.
c-The value of MFLOPS for co-processor system in configuration 2 is 80 MFLOPS.
d-The evaluation of your colleague is correct.
Explanation:
a
The MIPS rating equations are as follows
Configuration 01 (Processor only)
[tex]120\times 10^6=\dfrac{I+YF}{W}\\[/tex]
Configuration 02 (Processor + Co-processor)
[tex]80\times10^6=\dfrac{I+F}{B}[/tex]
b
From the equation, for processor and co-processor equation the value of B is calculated. For it to be calculated, the I value is calculated from the processor configuration with the following data F= 8 * 10^6 . Y= 50, W = 4 sec:
[tex]I=120\times10^6\timesW-YF\\I=(120\times10^6\times4)-(8\times10^6\times50)\\I=80\times10^6 \text{instructions}[/tex]
Using this value of I gives
[tex]B=\dfrac{I+F}{80\times10^6}\\B=\dfrac{80\times10^6+8\times10^6}{80\times10^6}\\B=\dfrac{88\times10^6}{80\times10^6}\\B=1.1\text{second}[/tex]
The value of B is 1.1 second.
c
The MFLOPS rating of configuration 2 is given as
[tex]\text{MFLOPS}=\dfrac{F}{B-\dfrac{I}{MIPS_{proc+coproc}}}\\\text{MFLOPS}=\dfrac{8\times10^6}{1.1-\dfrac{80\times10^6}{80\times10^6}}\\\text{MFLOPS}=\dfrac{8\times10^6}{1.1-1}\\\text{MFLOPS}=\dfrac{8\times10^6}{0.1}\\\text{Processor+Coprocessor MFLOPS}=80 \text{MFLOPS}[/tex]
So the value of MFLOPS for co-processor system in configuration 2 is 80 MFLOPS.
d
The value of W is 4 seconds while the value of B is 1.1 seconds. Despite being the configuration with lower MIPS, the co-processor configuration has a lower execution rate and thus the evaluation of your colleague is correct.
