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At a certain temperature this reaction follows second-order kinetics with a rate constant of 14.1·M−1s−1 : →2SO3g+2SO2gO2g Suppose a vessel contains SO3 at a concentration of 1.44M . Calculate the concentration of SO3 in the vessel 0.240 seconds later. You may assume no other reaction is important. Round your answer to 2 significant digits.

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Answer:

[tex][SO_3]=0.25M[/tex]

Explanation:

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In this case, since the integrated rate law for a second-order reaction is:

[tex][SO_3]=\frac{[SO_3]_0}{1+kt[SO_3]_0}[/tex]

Thus, we plug in the initial concentration, rate constant and elapsed time to obtain:

[tex][SO_3]=\frac{1.44M}{1+14.1M^{-1}s^{-1}*0.240s*1.44M}\\\\[/tex]

[tex][SO_3]=0.25M[/tex]

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