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Consider the following precipitation reaction:
2Na3PO4 (aq) + 3CuCl2 (aq) → Cu3(PO4)2(s) +6NaCl(aq)

What volume of 0.158 M Na3PO4 solution is necessary to completely react with 88.0 mL of 0.109 M CuCl2?
(Express your answer in millimeters)

Respuesta :

hazzagreen122
6.47 x 10-3 mol / V = 0.183 M = 0.183 ml

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