Step-by-step explanation:
If the triangle is right, we can use Pitagora
We can have 2 results
1.
[tex] \sqrt{ {6}^{2} + {8}^{2} } = \\ = \sqrt{36 + 64} = \\ = \sqrt{100} \\ = 10[/tex]
2.
[tex] \sqrt{ {8}^{2} - {6}^{2} } = \\ = \sqrt{64 - 36} = \\ = \sqrt{28 } \\ = 2 \sqrt{7} [/tex]
