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6⋅10 −2 6, dot, 10, start superscript, minus, 2, end superscript is how many times as large as 2 ⋅ 1 0 − 8 2⋅10 −8 2, dot, 10, start superscript, minus, 8, end superscript?

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abidemiokin

Answer:

6⋅10^ −2 is 3* 10^6 greater than 2 ⋅ 10^− 8

Step-by-step explanation:

Given the following expression

6⋅10^ −2 and 2 ⋅ 10^− 8

Taking their ratio

k = 6⋅10^ −2/2 ⋅ 10^− 8

k = 6/2 * 10^-2/10^-8

k = 3 * 10^{-2+8}

k = 3* 10^6

Hence 6⋅10^ −2 is 3* 10^6 greater than 2 ⋅ 10^− 8

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