mary need 50 ft of fence to protect her rectangular garden from squirrels. How long and how wide is the 8 ft more than the width length is if the length is 8 ft more than the width

Respuesta :

Answer:

Width of the fence = 8.5 ft

Length of the fence = 16.5 ft

Step-by-step explanation:

Mary need 50 feet of fence to protect her rectangular garden from squirrels. How long and wide is the garden if the length is 8 feet more than the width?

Perimeter of the fence = 2(length + width)

Perimeter of the fence = 50 ft

Width of the fence = x ft

Length of the fence = x + 8 ft

Perimeter of the fence = 2(length + width)

50 = 2{(x+8) + (x)}

50 = 2(x + 8 + x)

50 = 2(2x + 8)

50 = 4x + 16

50 - 16 = 4x

34 = 4x

x = 34/4

x = 8.5

Width of the fence = x ft

= 8.5 ft

Length of the fence = x + 8 ft

= 8.5 + 8

= 16.5 ft

Width of a rectangle is equal to [tex]\boldsymbol{8.5}[/tex] feet and length is equal to [tex]8.5+8=\boldsymbol{16.5}[/tex] feet

Perimeter of a rectangle

A quadrilateral having four right angles is known as a rectangle. It can also be described as a square - shaped quadrilateral (equiangular meaning all angles are identical) or a parallelogram with a right angle.

Let [tex]x[/tex] denotes the width [tex](w)[/tex] of a rectangle.

So,

Length of a rectangle [tex](l)=x+8[/tex]

Perimeter of a rectangle [tex]=50[/tex] feet

[tex]2(l+w)=50\\l+w=25\\x+8+x=25\\2x=17[/tex]

[tex]x=8.5[/tex] feet

So,

width is equal to [tex]\boldsymbol{8.5}[/tex] feet and length is equal to [tex]8.5+8=\boldsymbol{16.5}[/tex] feet

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