Answer:
Step-by-step explanation:
For each outcome there are
s!/(n!(s-n)!) combinations
where s is the number of selections and n is the number of specific outcomes
The probability of any specific outcome for 6 tosses of a coin is (1/2)^6
[(1/2)^6]*[(6!/6!)+(6!/(5!)+(6!/(4! 2!)+(6!/(3! 3!)]
(1/2)^6*(1+6+15+20)
42(1/2)^6
42(1/64)
42/64
21/32 which is 0.65625
0.656 (rounded to nearest thousandth)
