Answer:
[tex] 2228 \: {ft}^{2} [/tex]
Step-by-step explanation:
Required flooring cover
= Area of the school playground
= Area of square with side 40 ft + Area of semicircle with radius (40/2) i.e. 20 ft
[tex] = {(40)}^{2} + \frac{1}{2} \times 3.14 \times {(20)}^{2} \\ \\ = 1600 + \frac{1}{2} \times 3.14 \times 400 \\ \\ = 1600 + 3.14 \times 200 \\ \\ = 1600 + 628 \\ \\ = 2228 \: {ft}^{2} [/tex]
