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A heterogeneous ore mixture contains 35.0 % In2O3 by mass. How many tons of the ore must be mined to provide 325.0 kg of indium metal? (2000 lb = 1 ton, assume exact)

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ogorwyne

Answer:

1.2375 ton of ore

Explanation:

Mass of indium = 325

Formula = In2O3

Molar mass = 277.64 g/mol

Molar mass of indium = (2*114.8)g

229.6 indium is in 277.64 of In2O3

Mass of In2O3 required = 277.64/229.6 x 325

= 392.94kg

35 % In2O3 in ore

For 35 kg = 100 kg required

For 392.94,

100/35 x 392.94

= 1122.686 kg

1122.68 x 2.2

= 2469.9 pounds

2469.9/200

= 1.235 tons of ore

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