Answer: 18.0 moles of [tex]BH_3[/tex] will be produced when 27.0 moles of [tex]H_2[/tex] completely react.
Explanation:
The balanced chemical equation is:
[tex]2B+3H_2\rightarrow 2BH_3[/tex]
According to stoichiometry :
3 moles of [tex]H_2[/tex] produce = 2 moles of [tex]BH_3[/tex]
Thus 27.0 moles of [tex]H_2[/tex] will produce=[tex]\frac{2}{3}\times 27.0=18.0 moles[/tex] of [tex]BH_3[/tex]
Thus 18.0 moles of [tex]BH_3[/tex] will be produced when 27.0 moles of [tex]H_2[/tex] completely react.
