Answer:
The height of the hill is "31.85 m".
Explanation:
The given value is:
Velocity,
v = 25 m/s
As we know,
⇒ [tex]Kinetic \ energy =Potential \ energy[/tex]
i.e,
⇒ [tex]mgh=\frac{1}{2} mv^2[/tex]
⇒ [tex]gh=\frac{1}{2} v^2[/tex]
⇒ [tex]h=\frac{v^2}{2g}[/tex]
On substituting the given value, we get
⇒ [tex]h=\frac{(25)^2}{2\times 9.81}[/tex]
⇒ [tex]=\frac{625}{19.62}[/tex]
⇒ [tex]=31.85 \ m[/tex]
Given;
We know the relation,
→ [tex]Kinetic \ energy (K.E) = Potential \ energy (P.E)[/tex]
or,
→ [tex]mgh = \frac{1}{2}mv^2[/tex]
or,
→ [tex]gh = \frac{1}{2}v^2[/tex]
[tex]h = \frac{v^2}{2g}[/tex]
By putting the values, we get
[tex]= \frac{(25)^2}{2\times 9.81}[/tex]
[tex]= \frac{625}{19.62}[/tex]
[tex]= 31.85 \ m[/tex]
Thus the response above is right.
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