Answer:
A = 4.49
α = 57.72°
Explanation:
Knowing the magnitude of x & y of a vector we can determine the total magnitude of a vector.
[tex]A=\sqrt{A_{x}^{2} +A_{y}^{2} } \\A=\sqrt{(2.4)^{2} +(3.8)^{2} }\\A=4.49[/tex]
The angle tangent can be used to determine the angle.
[tex]tan(\alpha )=\frac{3.8}{2.4}\\tan(\alpha ) =1.5833\\\alpha =tan^{-1}(1.5833) \\\alpha = 57.72 (deg)[/tex]
