Answer:
the distance traveled by the dog is 27.18 m.
Explanation:
Given;
initial velocity of the dog, u = 7.92 m/s
final velocity of the dog, v = 3.22 m/s
time of motion, t = 4.88 s
The distance traveled by the dog is calculated as;
[tex]s = (\frac{v+u}{2} )t\\\\s = (\frac{7.92 + 3.22}{2} )(4.88)\\\\s = 27.18 \ m[/tex]
Therefore, the distance traveled by the dog is 27.18 m.
