Respuesta :

Answer:

[tex] {b}^{28} [/tex]

Step-by-step explanation:

[tex] { \bigg( \frac{ {b}^{19} }{ {b}^{12} } } \bigg)^{4} \\ \\ = { \bigg( { {b}^{19 - 12} }} \bigg)^{4} \\ \\ = { \bigg( { {b}^{7} }} \bigg)^{4} \\ \\ = {b}^{7 \times 4} \\ \\ = {b}^{28} [/tex]

6.28477 If I’m correct
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