Answer:
No of total brown = 2 + 1 = 3 .
probability = 3 / 6
= 1 /2 .
no of males = 2
probability
= 2 / 6
= 1 /3
no of person who is both male and brown = 1
probability = 1 /6
Required probability
= probability of being brown + probability of being male - probability of being both
= 1 / 2 + 1 / 3 - 1 /6
= 4 / 6
= 2 / 3 .
Step-by-step explanation: im
wrong?
