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A tightrope walker attaches a cable to the roofs of two adjacent buildings. The cable is 21.5 m long. The angle of inclination of the cable is 12 degrees. The buildings are 21.0 m apart. The shorter building is 10.0 m high. What is the height of the taller building?

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nuhulawal20

Answer:

the height of the taller building is 14.47 m

Step-by-step explanation:

Given the data in the question as illustrated in the image below.

form the image; ( Triangle BDE )

we know that sin∅ i= opposite/hypotenuse

so; sin12° = BE / 21.5

BE = 21.5sin12°

BE = 4.47 m

since, EA = DC = 10 m

BA = BE + EA

BA = 4.47 m + 10 m

BA = 14.47 m

Therefore, the height of the taller building is 14.47 m

Ver imagen nuhulawal20

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