PLEASE HELP ME


If a small planet were located 8.0 times as far from the sun as the Earth is, how many years would the planet take to orbit the sun?

Respuesta :

Answer:

the time period is 22.63 years

Explanation:

The computation of the number of years taken is as follows:

According to the Keplers law

[tex]T^2 \propto R^3[/tex]

Here T denotes the time period

And, R denotes the average distance among the sun and planet

Now let us assume for earth

R_1 & T_1 be 1 year

So, for Planet

[tex]R_2 = 8R_1 , T_2 = ?[/tex]

Now applied Keplers law

[tex](\frac{T_2}{T_1})^2 \propto (\frac{R_2}{R_1})^3\\\\(T_2)^2 = (\frac{8R_1}{R_1})^3 \times 1^2\\\\(T_2)^2 = 512\\\\T_2 = 22.674[/tex]

So, the time period is 22.63 years