Answer:
12.64 (unrounded)
Step-by-step explanation:
formula; a^2+b^2=c^2
you have your given which is 3 and hypotenuse of 13
plug in 3^2+b^2=13^2
solve 9+b^2=169
subtract 9 to the right side
169-9=160
bring down b^2=160
get rid of the square so [tex]\sqrt{160}[/tex]
which will be 12.64 unrounded
