Answer:
b
. 0.351 L.
Explanation:
Hello!
In this case, since diluted solutions are prepared by adding an extra amount of diluent to a stock-concentrated solution, we infer that the number of moles of solute remains the same, therefore we can write:
[tex]C_1V_1=C_2V_2[/tex]
Thus, solving for the volume of the stock solution, V1, we obtain:
[tex]V_1=\frac{C_2V_2}{C_1}[/tex]
Now, by plugging in the given data we obtain:
[tex]V_1=\frac{1.2M*0.585L}{2.0M}\\\\V_1=0.351L[/tex]
Therefore, the answer is b
. 0.351 L.
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