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A basketball player is 7 feet tall and releases the ball when his hands are 8 feet into the air at a velocity of 12 feet per second. Based on the pull of gravity, write a
model to show when the ball reach the basketball hoop which is the standard regulation of 10

Respuesta :

MrRoyal

The model of the ball path is s(t) = -16t² + 12t + 8

How to model the ball path?

The given parameters are:

  • Height of player =7 feet
  • Initial height of ball = 8 feet
  • Velocity = 12 feet per seconds

As a standard form, the path followed by the ball is represented as follows:

s(t) = h + vt - 0.5gt²

Where:

  • h represents the initial height; h = 8
  • v represents velocity of the ball = 12
  • g represents the acceleration due to gravity, g = 32

So, we have:

s(t) = 8 + 12t - 0.5 * 32t²

Evaluate

s(t) = 8 + 12t - 16t²

Rewrite as:

s(t) = - 16t² + 12t + 8

Hence, the model of the ball path is s(t) = -16t² + 12t + 8

Read more about quadratic functions at:

https://brainly.com/question/16272865

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