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Determine how many moles of Ba(OH) 2 are required to completely neutralize 0.431 mole of HC2H3O2

Respuesta :

Willchemistry
Mole ratio:

Ba(OH)₂ + 2 HC₂H₃O₂ = Ba(C₂H₃O₂)₂ + 2 H₂O

1 mole Ba(OH)₂ ----------- 2 moles HC₂H₃O₂
?? moles ------------------- 0.431 moles HC₂H₃O₂

0.431 x 1 / 2 => 0.2155 moles of Ba(OH)₂

Answer:

The moles of barium hydroxide required for neutralization is 0.2155 moles.

Explanation:

[tex]Ba(OH)_2+2CH_3COOH\rightarrow Ba(CH_3COO)_2+2H_2O[/tex]

According to the reaction, 2 moles of acetic acid reacts with 1 mole of barium hydroxide .

Then 0.431 mol of acetic acid will react with:

[tex]\frac{1}{2}\times 0.431mol=0.2155 mol[/tex] of barium hydroxide.

The moles of barium hydroxide required for neutralization is 0.2155 moles.

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