The male and female guests attending Patricia's party were surveyed to see if they drove to the party or did not drive. The data is displayed in the table below: Male Female Drove to the party 26 24 Did not drive to the party 34 116 If a guest is chosen at random from this group, what are the chances of choosing a guest who is male and did not drive to the party?
The question asks for a random guest chosen randomly; so we know that there are a total of 200 guests. I got 200 by adding both male and female drivers and non-drivers.
Specifically, the question asks for male non-drivers. There are 34 male non-drivers out of 200 total guests.
Picking a male non-driver out of total guests results in this fraction: 34/200
We can simplify this fraction by dividing both sides by 2 since it can divide both numbers.
Once we do that, we get 17/100.
A percent is a number out of 100 and we know that number. It's 17, so we can say there's 17% a male non-driver would be picked out of the guests.
Hope this helped. If you have any questions, leave a comment. Good luck!
