r = revenue r = (12.50 + 0.5x)(1800 - 60x)r = -30x2 + 150x + 22500r = -30(x2 - 150x - 750)r = -30(x - 30)(x + 25) {-25, 30} The zeros are -25 and 30.The maximum occurs at 2.5.Since the price increases by 50 cent increments, the maximum would happen at x = 2 or x = 3The tickets can be either $13.50 or $14.00.
