Answer:
Q = 12.5 kJ
Explanation:
Given that,
Mass of water, m = 50 mL = 0.05 kg
The temperature changes from 0 degree Celsius to 60 degree Celsius.
We need to find how much energy she use to heat the water. The energy required to heat the water is given by :
[tex]Q=mc\Delta T[/tex]
Where c is specific heat of water, c = 4186 J/kgºC
[tex]Q=0.05\times 4186 \times (60-0)\\\\=12558\ J[/tex]
or
Q = 12.5 kJ
So, the energy used to heat th water is 12.5 kJ.
