Respuesta :

➨ Let (x+2) = a ➩ [tex]xa+1a[/tex]

Then we factor a-term out of the expression ➩ Common Factor ➩ [tex]a(x+1)[/tex]

Then convert from a back to x+2

Thus, our answer would be ➩ [tex](x+2)(x+1)[/tex]

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