A car has wheels with a 9 inch radius. If each wheel's rate of turn is 6 revolutions per second, how fast is the car moving in units of inches/sec

Respuesta :

Answer:

v = 339,3 in/sec

Step-by-step explanation:

The wheels are moving at a rate of 6 rps (revolutions per second), and the length of the wheel is (L) is

L = 2*π*r        where r is a radius of the wheel

L = 2*π*9   (in)

L = 56,55 ( in)

L will be the traveled length by car in each turn of the wheel

Since the wheel has a rate of 6 turns by second, then we need to multiply de numbers of turns by second  times, the traveled length in 1 turn, in order to get the speed of the car

Then:

v ( speed of the car ) is:

v = 6 * 56,55 ( in/sec)

v = 339,3 in/sec

Angular speed tails that how fast a object resolves.the car is moving with the velocity of 339.43 inches/second.

To find the angular speed of the wheel, we need to know about the angular speed.

What is angular speed?

Angular speed is the rate of change of angle with respect to time of an object. Angular speed tails that how fast a object resolves.

It can be given as,

[tex]\omega=\dfrac{v}{r}[/tex]

Here,  is the [tex]v[/tex] linear velocity and [tex]r[/tex] is the radius.

Given information-

The radius of the wheels of the car is 9 inch.

The revolutions per second of the each wheel is 6 rpm.

As the wheel rotates at 6 revolutions per seconds. The one rev/sec equals to the [tex]2\pi[/tex] rad.

Thus the angular velocity is,

[tex]w=2\pi N[/tex]

[tex]\omega=2\pi \times 6\\\omega=12\pi[/tex]

Put the values in the above formula,

[tex]\omega=\dfrac{v}{r}\\12\pi=\dfrac{v}{9}\\[/tex]

Solve for [tex]v[/tex]

[tex]v=9\times12\pi\\v=9\times12 \times\dfrac{22}{7} \\v=339.43[/tex]

Hence the car is moving with 339.43 inches/second.

Learn more about the angular speed here;

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