[tex]\underline{\underline{\sf \bigstar \qquad Solution \qquad \: \bigstar}} \\ [/tex]
- Copper and Zinc in the ratio = 3:19
- Weight of copper in chemical = 874 grams
Let weight of copper be 3x and weight of zinc be 19x.
☯ [tex]\underline{\boldsymbol{According\: to \:the\: Question\:now :}} \\[/tex]
[tex]:\implies \textsf {Total weight = weight of copper + weight of zinc} \\ \\ \\ [/tex]
[tex]:\implies \textsf {Total weight = 3x +19x} \\ \\ \\ [/tex]
[tex]:\implies \underline{ \boxed{ \textsf {Total weight = 22x}}} \\ \\ \\ [/tex]
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[tex]\dashrightarrow\:\:\textsf{ Weight of chemical = weight of zinc + weight of copper} \\ \\ \\ [/tex]
[tex]\dashrightarrow \: \: \sf 22x = 3x + 19x \\ \\ \\ [/tex]
[tex]\dashrightarrow \: \: \sf 22x = 3x + 874 \\ \\ \\ [/tex]
[tex]\dashrightarrow \: \: \sf 22x - 3x = 874 \\ \\ \\ [/tex]
[tex]\dashrightarrow \: \: \sf 19x = 874 \\ \\ \\ [/tex]
[tex]\dashrightarrow \: \: \sf x = \dfrac{874}{19} \\ \\ \\ [/tex]
[tex]\dashrightarrow \: \: \underline{\boxed{ \sf x = 46}} \\ \\ \\[/tex]
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[tex]\bigstar\:\underline{\frak{Finding \: the \: weight \: of \: the \: zinc \: in \: a \: chemical : }}[/tex]
[tex]\longrightarrow\:\:\sf weight \: of \: zinc = 3x \\ \\ \\ [/tex]
[tex]\longrightarrow\:\:\sf weight \: of \: zinc = 3 \times 46 \\ \\ \\ [/tex]
[tex]\longrightarrow\:\: \underline{ \boxed{\sf weight \: of \: zinc =138 \: grams}} \\ \\ \\ [/tex]
[tex]\therefore\:\underline{\textsf{The chemical contains \textbf{138 grams}} \textsf{ of zinc}}. \\ [/tex]
