The width of a rectangle is 1/4 its length. The perimeter of the rectangle is 375 ft. What is the length, in feet, of the rectangle?

Respuesta :

Answer:

Required Answer:-

Let

[tex]\sf length=x [/tex]

[tex]\sf Breadth={\dfrac {x}{4}}[/tex]

As we know that in a rectangle

[tex]{\boxed{\sf Perimeter=2 (l+b)}}[/tex]

  • Substitute the values

[tex]{:}\longrightarrow\sf 2 \left (x+{\dfrac {x}{4}}\right)=375 [/tex]

[tex]{:}\longrightarrow\sf 2 \left({\dfrac {4x+x}{4}}\right)=375 [/tex]

[tex]{:}\longrightarrow\sf 2 \left({\dfrac {5x}{4}}\right)=375 [/tex]

[tex]{:}\longrightarrow\sf {\dfrac {10x}{4}}=375 [/tex]

[tex]{:}\longrightarrow\sf 10x=4×375 [/tex]

[tex]{:}\longrightarrow\sf 10x=1500 [/tex]

[tex]{:}\longrightarrow\sf x={\dfrac {1500}{10}}[/tex]

[tex]{:}\longrightarrow\sf x=150[/tex]

[tex]\therefore[/tex]Length =150feet