Answer:
y(t) = [tex]\frac{3Q}{2A} ( t - 1/2 sin2t ) - \frac{Q}{A} t + C[/tex]
Explanation:
Given data :
storage tank contains a liquid at depth ; Y
when tank is half full ; y = 0
flow rate = q
sinusoidal rate = 3Q [tex]sin^{2} (t)[/tex]
Determine how the equation can be written for this system
solution is attached below
note ; from the question it can be seen that the surface area ( A ) is constant
