Answer:
750 nm
Explanation:
It is given that,
Third minimum is at an angle of 48.6º when it falls on a single slit of width 3.00 μm.
We need to find the wavelength of the light. For a single slit experiment, the relation between wavelength and slit width is given by :
[tex]d\sin\theta=n\lambda[/tex]
For third minimum, n = 3
[tex]\lambda=\dfrac{d\sin\theta}{n}\\\\\lambda=\dfrac{3\cdot10^{-6}\cdot\sin48.6}{3}\\\\\lambda=7.5\times 10^{-7}\ m\\\\\lambda=750\ nm[/tex]
So, the wavelength of light is 750 nm.
