The question is incomplete. Here is the complete question.
If R is the midpoint of QS, [tex]RS=2x-4[/tex], ST = [tex]4x-1[/tex] and RT = [tex]8x-43[/tex], find QS.
Answer: QS = 68 units
Step-by-step explanation: The figure below shows a line segment QT.
To determine QS, first, determine value of x:
RT = RS + ST
[tex]8x-43=2x-4+4x-1[/tex]
[tex]8x-43=6x-5[/tex]
2x = 38
x = 19
Now, we determine QS:
Midpoint is a point dividing a line segment in two equal parts.
Then, QR = RS.
QS = QR + RS
QS = 2RS
[tex]QS=2(2x-4)[/tex]
[tex]QS=4x-8[/tex]
Substituting x = 19:
[tex]QS=4.19-8[/tex]
QS = 68
The segment QS is 68 units.
Answer: x = 1
Step-by-step explanation:
I have no idea what the actual answer is, as you didn't ask a question. So i'm assuming that you want the value of x.
Step 1: Draw a line containing all the points
R is in between point Q and point S, while T is last, based on alphabetical order.
Illustration:
2x - 4 Tx - 1
Q R S T
8x - 43
Step 2: Find T's value
To find t, create the substitution equation RS + ST = RT
2x - 4 + tx - 1 = 8x - 43
-2x -2x
-4 + tx - 1 = 6x - 43
tx - 5 = 6x - 43
tx = 6x - 38
tx/x = 6x/x - 38
t = 6 - 38
t = -32
This is the value of t
By the way, there is no correlation between point T and the variable t.
Step 3: Find x's value
Now that we know what t is, we can solve for x
2x - 4 -32x - 1 = 8x - 43
-30x - 5 = 8x - 43
+30x +30x
-5 = 38x - 43
+43 +43
38 = 38x
38/38 = 38x/38
1 = x
This is the value of x
