Answer:
v = 15.72 mi/hr
Explanation:
It is given that,
Steve Cram of Great Britain ran a mile in 3.81 min
We need to find Steve's average velocity in mi/hr.
Speed,
[tex]v=\dfrac{d}{t}\\\\v=\dfrac{1\ \text{mile}}{3.81\ \text{}min}\\\\v=0.262\ mi/min[/tex]
We know that,
1 hour = 60 minute
So, average speed is :
[tex]v=\dfrac{0.262\ \text{mile}}{\text{min}}\\\\v=\dfrac{0.262\ \text{miles}}{\dfrac{1}{60}h}\\\\v=15.72\ mi/hr[/tex]
So, the average velocity is 15.72 mi/h.
