Answer:
[tex]0.0000708\ \text{mol/L}[/tex]
Explanation:
The nitrate concentration of the sample = [tex]4.39\ \text{mg/L}=4.39\times 10^{-3}\ \text{g/L}[/tex]
Molar mass of [tex]NO^-_3=62.0049\ \text{g/mol}[/tex]
The molar concentration is obtained when we divide the concentration by its molar mass in the approriate units.
[tex]\dfrac{4.39\times 10^{-3}}{62.0049}=0.0000708\ \text{mol/L}[/tex]
The molar concentration is [tex]0.0000708\ \text{mol/L}[/tex]
