Answer:
0.4 Kg
Explanation:
From the question given above, the following data were obtained from the question:
Acceleration (a) of block = 5 m/s²
Force in the right direction (Fᵣ) = 3 N
Force in the left direction (Fₗ) = 5 N
Mass (m) of block =...?
Next, we shall determine the net force acting on the block. This can be obtained as follow:
Force in the right direction (Fᵣ) = 3 N
Force in the left direction (Fₗ) = 5 N
Net force (Fₙ) =?
Fₙ = Fₗ – Fᵣ
Fₙ = 5 – 3
Fₙ = 2 N
Thus the net force acting on the block is 2 N to the left.
Finally, we shall determine the mass of the block as follow:
Acceleration (a) of block = 5 m/s²
Net force (Fₙ) = 2 N
Mass (m) of block =...?
Net force (Fₙ) = mass (a) × acceleration (a)
Fₙ = m × a
2 = m × 5
Divide both side by 5
m = 2/5
m = 0.4 Kg
Therefore, the mass of the block is 0.4 Kg
