solve for x in terms of n
please help
will give brainliest answer

Answer:
[tex]x=\sqrt{n-1}[/tex]
Step-by-step explanation:
[tex]1^{2} +x^{2} =\sqrt{n} ^{2}[/tex] solve for x & a square root squared cancels out
[tex]x^{2} =n-1[/tex]
[tex]x=\sqrt{n-1}[/tex]