You purchased concentrated cleaner that must be diluted (watered down) before use. Container A is the cleaner, which is a 30% solution. Container B is pure water. You are mixing together the contents of Container A and Container B to produce 60 gallons of 8% solution. How many gallons from each container are needed to create the 60 gallons of 8% cleaning solution? Write your answers as integers only.

Container A: 30% Cleaning Solution =
gallons

Container B: Pure Water =
gallons

We need to mix two components (a cleaner that is 30% solution and pure water) such that we end with 60 gallons of 8% solution, and we want to know the volume of each of these two components that we need to use.

The solution is:

Container A: 30% Cleaning Solution = 16 gallons

Container B: Pure Water = 44 gallons

------------------------------------------

Now let's see how to solve this:

Let's start by defining variables:

x = volume of water used.
y = volume of cleaner used.

We know that we want to get 60 gallons, so we have that:

x + y = 60 gal.

And we want this to be an 8%, then we must have that the amount of solution on the left side is equal to the amount of solution on the right side.

on the left side the amount of solution is just 0.3*y
on the right side the amount of solution must be (60 gal)*0.08

(note that the percentages are used in decimal form).

Then we have:

0.3*y = (60 gal)*0.08

With this equation we can find the value of y:

y = (60 gal)*0.08/0.3 = 16 gal.

Now that we know the value of y, we can replace it in the equation:

x + y = 60 gal

to get the value of x:

x + 16gal = 60 gal

x = 60 gal - 16 gal = 44 gal.

So finally, we can conclude that you need to use 44 gallons of water and 16 gallons of cleaner.

If you want to learn more, you can read:

https://brainly.com/question/24395090