Answer:
[tex]P_2=2.04atm[/tex]
Explanation:
Hello.
In this case, by using the combined ideal gas law, we can identify the change in pressure, temperature an volume as shown below:
[tex]\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}[/tex]
In such a way, since we are asked to compute the final pressure, P2, we proceed as follows:
[tex]P_2=\frac{P_1V_1T_2}{T_1V_2} \\\\P_2=\frac{1.12atm*2.29L*302K}{285K*1.33L}\\ \\P_2=2.04atm[/tex]
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